5 moles required according to balanced reaction.
What is the total number of moles of O2 required for the complete combustion of one mole of benzene?
Since the molar mass of benzene is approximately 78.1 g/mol, 3.9/78.1 is about 0.0499 mol. Since the ratio of benzene to oxygen according to the equation is 2:15, or 1:7.5, the moles of oxygen needed is 0.0499 x 7.5, which is 0.374 mol.
What is the total number of moles of O2 required for the complete combustion of 1.5 moles of C3H8 G?
Answer Expert Verified
The consuming of reactants has the same ratio as the balanced equation. So the ratio of consuming C3H8 and O2 is equal to 1:5. So when 1.5 mol of C3H8 consumed, 1.5*5=7.5 mol O2 consumed.
How many moles of oxygen gas are required for the complete combustion of one mole of pentane?
Now, we can realize that the stoichiometric ratio of pentane to oxygen is 1:8 (from coefficients). Therefore, in order to completely combust 1 mol pentane , we must use 8mol O2−−−−−−−− .
What is the minimum number of moles of O2?
Answer: The minimum number of moles O2 needed is 0.50 moles (option B) The minimum number of moles O2 needed is 0.50 moles (option B)
How many moles of oxygen are needed for a complete combustion of 2 moles of butane?
Each mole of butane needs 6.5 moles of oxygen, so 13 moles of oxygen is required for 2 moles of butane in a complete combustion.
How many moles are in 12.0 grams of O2?
Therefore, 12 g of oxygen gas has 0.375 moles.
How do I calculate moles?
- First you must calculate the number of moles in this solution, by rearranging the equation. No. Moles (mol) = Molarity (M) x Volume (L) = 0.5 x 2. = 1 mol.
- For NaCl, the molar mass is 58.44 g/mol. Now we can use the rearranged equation. Mass (g) = No. Moles (mol) x Molar Mass (g/mol) = 1 x 58.44. = 58.44 g.
What is the total number of moles of C that must completely react to produce 2.0 moles of C2H6?
The answer is (4) 4.0 mol. This is a stoichiometry problem. You start with 2.0 mol of C2H6 and obtain the moles of C by multiplying 2.0 by the mole ratio, in this case 2. 2.0*2=4.0mol.
What is the mole ratio of oxygen to pentane?
Answer: The mole ratio of oxygen to pentane for the combustion of pentane is 8 : 1.
How many moles of o2 are required for the complete combustion of 2 moles of c2h4?
The complete combustion requires 1.527×1024molecules O2 . There are four steps to follow in this problem: Balance the equation.
What type of combustion is caused by a lack of oxygen?
Incomplete combustion occurs when there isn’t enough oxygen to allow the fuel to react completely with the oxygen to produce carbon dioxide and water, and also when the combustion is quenched by a heat sink such as a solid surface or flame trap.
What is the mole ratio of NO to NO2?
We are asked for the mole ratio between NO2 and NO N O 2 a n d N O . The coefficient in front of NO 2 in the balanced equation is 3 and the coefficient in front of NO is 1. Therefore, the mole ratio of NO2 to NO N O 2 t o N O is 3:1.
How many moles of kclo3 must completely react?
Therefore, 4 moles of potassium chlorate must be used to produce 6 moles of oxygen gas.
What is the total mass in grams of 0.75 mole so2?
1. 16 g.