# How many moles of oxygen will occupy a volume of 2 5 l at STP?

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So, there will be 0.122 moles of oxygen gas.

## How many moles of oxygen will occupy a volume of 2.5 liters at 1.2 atm and 25 C or 298k?

How many moles of oxygen will occupy a volume of 2.5 liters at 1.2 atm and 25° C? PV = V (1.2 n. 0821) (298) = 123 mols 2.

## How many moles of oxygen gas are in a 22.4 L volume at STP?

Assuming that the gas is at standard temperature and pressure (STP), one mole of any gas occupies 22.4 L . This means the number of moles of O2 is 222.4=0.089 mol .

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## What is the volume of 2 moles of O2 at STP?

Answer. 1mol O2 occupies 22.4L of volume at STP. so 2mol O2 occupies 44.8L of volume at STP.

## How do you find volume of oxygen at STP?

7. Volume of oxygen at STP

1. P1 = 739.1 mm Hg.
2. V1 = 156.4 mL.
3. T1 = 294 K.
4. P2 = 760 mm Hg.
5. V2 = Volume at STP we want.
6. T2 = 273 K.

## At what temperature will 5g of Cl2 exert a pressure of 900?

P = 27.8atm

At what temperature will 5.00 g of Cl2 exert a pressure of 900.

## What volume in liters will 2.0 moles of nitrogen occupy at 720 atm and 20 degrees C?

The answer is consistent with the known molar volume under standard laboratory condiitions: 25.4⋅L at 1⋅atm and 298⋅K .

## What is the volume of 3 moles of oxygen at STP?

3 moles of oxygen at STP will occupy a volume of 3×22.

## How many moles of oxygen will occupy a volume of 2.5 liters?

So, there will be 0.122 moles of oxygen gas.

## What is STP formula?

STP in chemistry is the abbreviation for Standard Temperature and Pressure. STP most commonly is used when performing calculations on gases, such as gas density and is represented as STP = V*(273/T)*(P/100) or stp = Volume of Gas*(273/Temperature of Gas)*(Pressure of Gas/100).

## What is the volume of 2 moles of gas at STP?

2: A mole of any gas occupies 22.4L at standard temperature and pressure (0oC and 1atm).

## What is the volume of 0.50 moles of oxygen gas o2 at STP?

Well, the molar volume at STP is 22.4⋅L⋅mol−1 . I make it approx. 400⋅mL .

## How much volume does 1 mole of oxygen occupy?

One mole of oxygen gas occupies 22.4 l volume at STP.

## What is the volume of 1 kg of oxygen?

The volume of 1kg of oxygen gas at NPT is 0.7m^(3) .

## How do you calculate the volume of oxygen?

Calculate the volume (in cubic meters) of gaseous oxygen using the ideal gas law: multiply the amount of oxygen (in moles) by temperature and the molar gas constant followed by dividing the product by pressure.

## What is the volume occupied by 3.2 g of oxygen at STP?

Answer: Volume occupied by the volume is 2.46 L. 