What is the mole ratio of Fe3O4 to FE?

2) In the case of Fe3O4 and Fe, the chemical equation is: Fe+H2O → Fe3O4+H2. 4) From that the mole ratios are: 3 mol Fe : 4 mol 4H2O : 1 mol Fe3O4 : 4 mol H2.

What is the mole mole ratio Fe2O3?

1:2:3.

What is the mole ratio of Fe?

The molar mass of Fe is 55.845 grams (1 mole Fe = 55.845 grams Fe). The molar mass of O2 is 2 x 16.00 or 32.00 grams (1 mole O2 = 32.00 grams O2). The mass of a mole of Fe2O3 is (2 x Fe) + (3 x Oxygen) = (2 x 55.845) + (3 x 16.00) = 159.69 grams (1 mole of Fe2O3 = 159.69 grams Fe2O3).

What is the mole ratio of Fe H2?

The 1:3. mole ratio that exists between the two reactants tells you that the reaction will always consume three times as many moles of hydrogen gas than of ferric oxide.

What is the mole mole ratio of KClO3 o2?

You’d need 33.3 moles of potassium chlorate, KClO3 , to produce that much oxygen. Notice that you have a 2:3. mole ratio between potassium chlorate and oxygen gas, which means that, regardless of how many moles of the former react, you’ll always produce 3/2 times more moles of the latter.

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What is the mole ratio of sodium hydroxide to water?

Two moles of sodium hydroxide on the other hand produces one mole of sodium sulfate (2:1 ratio) and 2 moles of water(1:1 ratio).

Do you reduce mole ratios?

The molar ratio can be constructed using any two compounds in the reaction, be they reactants or products. Write the molar ratios for (a) O2 to SO3 and (b) SO2 to SO3. … Note that both ratios can be reduced.

What is the mole ratio of oxygen to methane?

So the molar ratio of methane to oxygen is one to two, which means that for every one mole of methane, two moles of oxygen is needed to react with it.

What is the mole ratio of pcl3 to pcl5?

Answer : The mole ratio of to is 1 : 1 ratio.

What are the 4 types of stoichiometry problems?

4 types of stoichiometry problems

  • Mole – mole.
  • Mole – mass.
  • Mass – mole.
  • Mass – mass.

What is the mole ratio of O2 to C6H6?

The molar ratio of O2 to C6H6 is (15/2) or 7.5. Multiply this by the number of moles C6H6 and we’ll have the number of moles of O2 needed to combust all the C6H6. We find that 7.5 x 0.61 moles = 4.58 moles O2 required.

How do I calculate moles?

  1. First you must calculate the number of moles in this solution, by rearranging the equation. No. Moles (mol) = Molarity (M) x Volume (L) = 0.5 x 2. = 1 mol.
  2. For NaCl, the molar mass is 58.44 g/mol. Now we can use the rearranged equation. Mass (g) = No. Moles (mol) x Molar Mass (g/mol) = 1 x 58.44. = 58.44 g.
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Where are the numbers for a mole ratio found?

Where are the numbers for a mole ratio found? They are part of the chemical formulas for the reactants / products. They are given in the problem. They are found on the periodic table for those elements.

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